In ΔABC, ∠CAD = 22° and segment CB = 15 cm. If the cos of 22° = 0.9272, then the sin of ∠C = _______.
Accepted Solution
A:
You can calculate [tex]\sin22^{\circ}[/tex] using formula: [tex]\cos^222^{\circ}+\sin^222^{\circ}=1[/tex]. Then [tex]\sin^222^{\circ}=1-\cos^222^{\circ}[/tex] and [tex]\sin^222^{\circ}=1-( 0.9272)^2=0.14030016 \\ \sin22^{\circ}= \sqrt{0.14030016} =0.3746[/tex]. Answer: [tex]\sin22^{\circ}=0.3746[/tex]