MATH SOLVE

2 months ago

Q:
# Select the correct answer from each drop-down menu.Emily is playing a board game that has a spinner divided into equal sections numbered 1 to 18.The probability of the spinner landing on an even number or a multiple of 3 is . The probability of the spinner landing on an odd number or a number between 4 and 15 (both numbers excluded) is .Reset Next

Accepted Solution

A:

Answer:The probability of the spinner landing on an even number or a multiple of 3 is 0.6667
.The probability of the spinner landing on an odd number or a number between 4 and 15 (both numbers excluded) is 0.7778
.Step-by-step explanation:Be the events
A = even number
B = Multiple of 3
C = Odd Number
D = Number between 4 and 15, both numbers excluded
The sets are as follows:
A = {2,4,6,8,10,12,14,16,18} B = {3,6,9,12,15,18} C = {1,3,5,7,9,11,13,15,17} D = {5,6,7,8,9,10,11,12,13,14} To calculate the probability that the roulette lands in an even number or in a multiple of 3, we make the union of A and B:
A U B = {2,3,4,6,8,9,10,12,14,15,16,18} = 12 numbers of 18
P (A U B) = 12/18 = 2/3 = 0.6667
To calculate the probability that roulette lands on an odd number or a number between 4 and 15 (both numbers excluded), we make the union of C and D:
C U D = {1,3,5,6,7,8,9,10,11,12,13,14,15,17} = 14 numbers of 18
P (C U D) = 14/18 = 7/9 = 0.7778
The first answer is 0.6667
The second answer is 0.7778
Hope this helps!