The graph of f(x) = x3 + 6x2 + 12x + 8 is shown. Based on the graph, how many real number solutions does the equation x3 + 6x2 + 12x + 8 = 0 have?
Accepted Solution
A:
You didn't show the graph. Anyway, that equation is a perfect cube and equals (x +2)^3 or (x +) * (x +) * (x +) Therefore, it has 3 real number solutions and ALL of those solutions equal -2 Β