Two bottling plants package a certain type of sports drink. Suppose the mean volume of all of this type of sports drinks is 18 fluid ounces. Bottling plant A bottles approximately 48805 sports drinks per day. Bottling plant B bottles approximately 172594 sports drinks per day. On a particular day, which bottling plant is less likely to record a mean volume of 19 fluid ounces for the day?

Answer:So, since plant B bottles more drinks than plant A, it will be less likely to record a mean volume of 19 fluid ounces for the day.Step-by-step explanation:The general rule is that the larger the sample, the closer the sample mean will be to the population mean. This happens because the standard deviation of our sample is given by the following formula:[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]In which [tex]\sigma[/tex] is the standard deviation of the mean volume of all of this type of sports drinks and [tex]n[/tex] is the size of the sample. So as [tex]n[/tex] increases, the less variation there will be, and the closer the sample mean will be to the population mean.So, since plant B bottles more drinks than plant A, it will be less likely to record a mean volume of 19 fluid ounces for the day.